2x^2-3/4x=5

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Solution for 2x^2-3/4x=5 equation: 


x in (-oo:+oo)

2*x^2-((3/4)*x) = 5 // - 5

2*x^2-((3/4)*x)-5 = 0

2*x^2+(-3/4)*x-5 = 0

2*x^2-3/4*x-5 = 0

DELTA = (-3/4)^2-(-5*2*4)

DELTA = 649/16

DELTA > 0

x = ((649/16)^(1/2)+3/4)/(2*2) or x = (3/4-(649/16)^(1/2))/(2*2)

x = ((649/16)^(1/2)+3/4)/4 or x = (3/4-(649/16)^(1/2))/4

x in { (3/4-(649/16)^(1/2))/4, ((649/16)^(1/2)+3/4)/4 }

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